for d in results?; do cat $d/result$rate; done | awk '{sumreq[$1]+=$3; count[$1]++;} END {for(power in count){print power,sumreq[power]/count[power]}}' | sort -n

-- AmitaEkbote - 04 Aug 2009

 
Copyright 2016 The Board of Trustees
of the University of Illinois.webmaster@cs.uic.edu
WISEST
Helping Women Faculty Advance
Funded by NSF